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	<title>Arquivos Matemática IFFar - Ciência Exata</title>
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		<title>IFFar 2020 &#8211; Solução comentada</title>
		<link>https://cienciaexata.com/iffar-2020-solucao-comentada/</link>
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		<dc:creator><![CDATA[Ciência Exata]]></dc:creator>
		<pubDate>Wed, 04 Dec 2019 11:18:32 +0000</pubDate>
				<category><![CDATA[Resoluções Comentadas]]></category>
		<category><![CDATA[Matemática IFFar]]></category>
		<guid isPermaLink="false">https://cienciaexata.com/?p=4204</guid>

					<description><![CDATA[<p>Instituto Federal Farroupilha &#8211; Processo Seletivo 2020 dos Cursos Técnicos Integrados MATEMÁTICA Questão 9 Questão 10 Questão 11 Questão 12 Questão 13 Questão 14 Questão 15 Questão 16 Questão 9 Se é raiz da equação do primeiro grau , então o valor de “a” é: A) 5. B) 6. C) 7. D) 8. E) 9. ... </p>
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			<h3 class="elementor-heading-title elementor-size-default">Instituto Federal Farroupilha - Processo Seletivo 2020 dos Cursos Técnicos Integrados</h3>		</div>
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			<h3 class="elementor-heading-title elementor-size-default">MATEMÁTICA</h3>		</div>
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									<div id="elementor-tab-title-2621" class="elementor-tab-title elementor-tab-desktop-title" aria-selected="true" data-tab="1" role="tab" tabindex="0" aria-controls="elementor-tab-content-2621" aria-expanded="false">Questão 9</div>
									<div id="elementor-tab-title-2622" class="elementor-tab-title elementor-tab-desktop-title" aria-selected="false" data-tab="2" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2622" aria-expanded="false">Questão 10</div>
									<div id="elementor-tab-title-2623" class="elementor-tab-title elementor-tab-desktop-title" aria-selected="false" data-tab="3" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2623" aria-expanded="false">Questão 11</div>
									<div id="elementor-tab-title-2624" class="elementor-tab-title elementor-tab-desktop-title" aria-selected="false" data-tab="4" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2624" aria-expanded="false">Questão 12</div>
									<div id="elementor-tab-title-2625" class="elementor-tab-title elementor-tab-desktop-title" aria-selected="false" data-tab="5" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2625" aria-expanded="false">Questão 13</div>
									<div id="elementor-tab-title-2626" class="elementor-tab-title elementor-tab-desktop-title" aria-selected="false" data-tab="6" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2626" aria-expanded="false">Questão 14</div>
									<div id="elementor-tab-title-2627" class="elementor-tab-title elementor-tab-desktop-title" aria-selected="false" data-tab="7" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2627" aria-expanded="false">Questão 15</div>
									<div id="elementor-tab-title-2628" class="elementor-tab-title elementor-tab-desktop-title" aria-selected="false" data-tab="8" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2628" aria-expanded="false">Questão 16</div>
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									<div class="elementor-tab-title elementor-tab-mobile-title" aria-selected="true" data-tab="1" role="tab" tabindex="0" aria-controls="elementor-tab-content-2621" aria-expanded="false">Questão 9</div>
					<div id="elementor-tab-content-2621" class="elementor-tab-content elementor-clearfix" data-tab="1" role="tabpanel" aria-labelledby="elementor-tab-title-2621" tabindex="0" hidden="false"><p>Se <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+x%3D2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle x=2' title='\displaystyle x=2' class='latex' /> é raiz da equação do primeiro grau <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+ax%2B%28a-2%29%3D19&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle ax+(a-2)=19' title='\displaystyle ax+(a-2)=19' class='latex' />, então o valor de “a” é:<br />A) 5.<br />B) 6.<br />C) 7.<br />D) 8.<br />E) 9.</p><p><div class="su-spoiler su-spoiler-style-default su-spoiler-icon-caret su-spoiler-closed" data-scroll-offset="0" data-anchor-in-url="no"><div class="su-spoiler-title" tabindex="0" role="button"><span class="su-spoiler-icon"></span>SOLUÇÃO COMENTADA</div><div class="su-spoiler-content su-u-clearfix su-u-trim"> <br /><strong>Resposta: C</strong></p><p>
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	<iframe style="border: 0;" class="youtube-player" width="854" height="480" src="https://www.youtube.com/embed/FyVzCfXkI88?modestbranding=1&#038;rel=0&#038;start=23" allowfullscreen></iframe>
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									<div class="elementor-tab-title elementor-tab-mobile-title" aria-selected="false" data-tab="2" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2622" aria-expanded="false">Questão 10</div>
					<div id="elementor-tab-content-2622" class="elementor-tab-content elementor-clearfix" data-tab="2" role="tabpanel" aria-labelledby="elementor-tab-title-2622" tabindex="0" hidden="hidden"><p>O valor da expressão numérica <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+0%2C%5Coverline%7B3%7D%5Ctimes+%5Cleft+%28+0%2C5%2B%5Cfrac%7B3%7D%7B5%7D%2B%5Csqrt%7B121%7D-4%5E%7B1%2F2%7D+%5Cright+%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle 0,\overline{3}\times \left ( 0,5+\frac{3}{5}+\sqrt{121}-4^{1/2} \right )' title='\displaystyle 0,\overline{3}\times \left ( 0,5+\frac{3}{5}+\sqrt{121}-4^{1/2} \right )' class='latex' /> é:</p><p>A) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B11%7D%7B3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle \frac{11}{3}' title='\displaystyle \frac{11}{3}' class='latex' /></p><p>B) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B101%7D%7B30%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle \frac{101}{30}' title='\displaystyle \frac{101}{30}' class='latex' /></p><p>C) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7B3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle \frac{1}{3}' title='\displaystyle \frac{1}{3}' class='latex' /></p><p>D) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B11%7D%7B5%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle \frac{11}{5}' title='\displaystyle \frac{11}{5}' class='latex' /></p><p>E)  <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7B1%7D%7B5%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle \frac{1}{5}' title='\displaystyle \frac{1}{5}' class='latex' /></p><p><div class="su-spoiler su-spoiler-style-default su-spoiler-icon-caret su-spoiler-closed" data-scroll-offset="0" data-anchor-in-url="no"><div class="su-spoiler-title" tabindex="0" role="button"><span class="su-spoiler-icon"></span>SOLUÇÃO COMENTADA</div><div class="su-spoiler-content su-u-clearfix su-u-trim"> <br /><strong>Resposta: B</strong></p><p>
<div class="youtube-embed ye-container" itemprop="video" itemscope itemtype="https://schema.org/VideoObject">
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	<iframe style="border: 0;" class="youtube-player" width="854" height="480" src="https://www.youtube.com/embed/FyVzCfXkI88?modestbranding=1&#038;rel=0&#038;start=122" allowfullscreen></iframe>
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									<div class="elementor-tab-title elementor-tab-mobile-title" aria-selected="false" data-tab="3" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2623" aria-expanded="false">Questão 11</div>
					<div id="elementor-tab-content-2623" class="elementor-tab-content elementor-clearfix" data-tab="3" role="tabpanel" aria-labelledby="elementor-tab-title-2623" tabindex="0" hidden="hidden"><p>Dois cabos de aço presos ao chão estão amarrados na ponta de um poste de altura H perpendicular ao chão, conforme mostrado na figura a seguir:</p><p><img fetchpriority="high" decoding="async" class="aligncenter size-full wp-image-4239" src="https://cienciaexata.com/wp-content/uploads/2019/12/q11_iffar.png" alt="" width="337" height="151" srcset="https://cienciaexata.com/wp-content/uploads/2019/12/q11_iffar.png 337w, https://cienciaexata.com/wp-content/uploads/2019/12/q11_iffar-300x134.png 300w" sizes="(max-width: 337px) 100vw, 337px" /></p><p>Se os cabos formam entre si um ângulo de 90°, então a altura do poste, em metros, é:<br />A) 8.<br />B) 9.<br />C) 10.<br />D) 11.<br />E) 12.</p><p><div class="su-spoiler su-spoiler-style-default su-spoiler-icon-caret su-spoiler-closed" data-scroll-offset="0" data-anchor-in-url="no"><div class="su-spoiler-title" tabindex="0" role="button"><span class="su-spoiler-icon"></span>SOLUÇÃO COMENTADA</div><div class="su-spoiler-content su-u-clearfix su-u-trim"><br /><strong>Resposta: E</strong></p><p>
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	<iframe style="border: 0;" class="youtube-player" width="854" height="480" src="https://www.youtube.com/embed/FyVzCfXkI88?modestbranding=1&#038;rel=0&#038;start=466" allowfullscreen></iframe>
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									<div class="elementor-tab-title elementor-tab-mobile-title" aria-selected="false" data-tab="4" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2624" aria-expanded="false">Questão 12</div>
					<div id="elementor-tab-content-2624" class="elementor-tab-content elementor-clearfix" data-tab="4" role="tabpanel" aria-labelledby="elementor-tab-title-2624" tabindex="0" hidden="hidden"><p>Um hexágono regular é tal que seu perímetro vale 12. A área desse hexágono regular é:</p><p>A) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+6%5Csqrt%7B3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle 6\sqrt{3}' title='\displaystyle 6\sqrt{3}' class='latex' />.</p><p>B) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+5%5Csqrt%7B3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle 5\sqrt{3}' title='\displaystyle 5\sqrt{3}' class='latex' />.</p><p>C) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+4%5Csqrt%7B3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle 4\sqrt{3}' title='\displaystyle 4\sqrt{3}' class='latex' />.</p><p>D) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+3%5Csqrt%7B3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle 3\sqrt{3}' title='\displaystyle 3\sqrt{3}' class='latex' />.</p><p>E) <img src='https://s0.wp.com/latex.php?latex=%5Cdisplaystyle+2%5Csqrt%7B3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\displaystyle 2\sqrt{3}' title='\displaystyle 2\sqrt{3}' class='latex' />.</p><p><div class="su-spoiler su-spoiler-style-default su-spoiler-icon-caret su-spoiler-closed" data-scroll-offset="0" data-anchor-in-url="no"><div class="su-spoiler-title" tabindex="0" role="button"><span class="su-spoiler-icon"></span>SOLUÇÃO COMENTADA</div><div class="su-spoiler-content su-u-clearfix su-u-trim"> <br /><strong>Resposta: A</strong></p><p>
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	<iframe style="border: 0;" class="youtube-player" width="854" height="480" src="https://www.youtube.com/embed/FyVzCfXkI88?modestbranding=1&#038;rel=0&#038;start=712" allowfullscreen></iframe>
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									<div class="elementor-tab-title elementor-tab-mobile-title" aria-selected="false" data-tab="5" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2625" aria-expanded="false">Questão 13</div>
					<div id="elementor-tab-content-2625" class="elementor-tab-content elementor-clearfix" data-tab="5" role="tabpanel" aria-labelledby="elementor-tab-title-2625" tabindex="0" hidden="hidden"><p>Dois triângulos ABC e A’B’C’ são semelhantes, sendo que a área do triângulo ABC é menor do que a área do triângulo A’B’C’. Se a área do triângulo ABC é 3 cm² e a razão de semelhança vale 4, então a área do triângulo A’B’C’ é:<br />A) 6 cm².<br />B) 12 cm².<br />C) 24 cm².<br />D) 48 cm².<br />E) 96 cm².</p><p><div class="su-spoiler su-spoiler-style-default su-spoiler-icon-caret su-spoiler-closed" data-scroll-offset="0" data-anchor-in-url="no"><div class="su-spoiler-title" tabindex="0" role="button"><span class="su-spoiler-icon"></span>SOLUÇÃO COMENTADA</div><div class="su-spoiler-content su-u-clearfix su-u-trim"> <br /><strong>Resposta: D</strong></p><p>
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	<iframe style="border: 0;" class="youtube-player" width="854" height="480" src="https://www.youtube.com/embed/dDPdz5zN65I?modestbranding=1&#038;rel=0&#038;start=7" allowfullscreen></iframe>
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									<div class="elementor-tab-title elementor-tab-mobile-title" aria-selected="false" data-tab="6" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2626" aria-expanded="false">Questão 14</div>
					<div id="elementor-tab-content-2626" class="elementor-tab-content elementor-clearfix" data-tab="6" role="tabpanel" aria-labelledby="elementor-tab-title-2626" tabindex="0" hidden="hidden"><p>As retas r, s e t, representadas na figura abaixo, são paralelas e as retas r’ e s’ são transversais.</p><p><img decoding="async" class="aligncenter size-full wp-image-4245" src="https://cienciaexata.com/wp-content/uploads/2019/12/q14_iffar.png" alt="" width="431" height="251" srcset="https://cienciaexata.com/wp-content/uploads/2019/12/q14_iffar.png 431w, https://cienciaexata.com/wp-content/uploads/2019/12/q14_iffar-300x175.png 300w" sizes="(max-width: 431px) 100vw, 431px" /></p><p>Se AB = 10, AC = 15 e A’C’ = 30, então a medida do segmento A’B’ é:<br />A) 20.<br />B) 15.<br />C) 10.<br />D) 5.<br />E) 2.</p><p><div class="su-spoiler su-spoiler-style-default su-spoiler-icon-caret su-spoiler-closed" data-scroll-offset="0" data-anchor-in-url="no"><div class="su-spoiler-title" tabindex="0" role="button"><span class="su-spoiler-icon"></span>SOLUÇÃO COMENTADA</div><div class="su-spoiler-content su-u-clearfix su-u-trim"> <br /><strong>Resposta: A</strong></p><p>
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									<div class="elementor-tab-title elementor-tab-mobile-title" aria-selected="false" data-tab="7" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2627" aria-expanded="false">Questão 15</div>
					<div id="elementor-tab-content-2627" class="elementor-tab-content elementor-clearfix" data-tab="7" role="tabpanel" aria-labelledby="elementor-tab-title-2627" tabindex="0" hidden="hidden"><p>Um produto custa R$ 240,00 para um comerciante. Se o comerciante deseja lucrar 20% na venda desse produto – com o lucro sendo sobre o <strong>preço de venda</strong>, o produto deverá ser vendido por:<br />A) R$ 274,00.<br />B) R$ 298,00.<br />C) R$ 300,00.<br />D) R$ 324,00.<br />E) R$ 367,00.</p><p><div class="su-spoiler su-spoiler-style-default su-spoiler-icon-caret su-spoiler-closed" data-scroll-offset="0" data-anchor-in-url="no"><div class="su-spoiler-title" tabindex="0" role="button"><span class="su-spoiler-icon"></span>SOLUÇÃO COMENTADA</div><div class="su-spoiler-content su-u-clearfix su-u-trim"> <br /><strong>Resposta: C</strong></p><p>
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									<div class="elementor-tab-title elementor-tab-mobile-title" aria-selected="false" data-tab="8" role="tab" tabindex="-1" aria-controls="elementor-tab-content-2628" aria-expanded="false">Questão 16</div>
					<div id="elementor-tab-content-2628" class="elementor-tab-content elementor-clearfix" data-tab="8" role="tabpanel" aria-labelledby="elementor-tab-title-2628" tabindex="0" hidden="hidden"><p>Considere o triângulo retângulo ABC representado na figura abaixo.</p><p><img decoding="async" class="aligncenter size-full wp-image-4246" src="https://cienciaexata.com/wp-content/uploads/2019/12/q16_iffar.png" alt="" width="263" height="161" /></p><p>Se BC = 18, então a medida do segmento AB é:<br />A) 5.<br />B) 6.<br />C) 7.<br />D) 8.<br />E) 9.</p><p><div class="su-spoiler su-spoiler-style-default su-spoiler-icon-caret su-spoiler-closed" data-scroll-offset="0" data-anchor-in-url="no"><div class="su-spoiler-title" tabindex="0" role="button"><span class="su-spoiler-icon"></span>SOLUÇÃO COMENTADA</div><div class="su-spoiler-content su-u-clearfix su-u-trim"> <br /><strong>Resposta: E</strong></p><p>
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		<p>O post <a href="https://cienciaexata.com/iffar-2020-solucao-comentada/">IFFar 2020 &#8211; Solução comentada</a> apareceu primeiro em <a href="https://cienciaexata.com">Ciência Exata</a>.</p>
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